construct a quadrilateral PQRS where PQ = 5.4 cm, angle P is 60°, angle Q is 105°, angle R is 75°, angle S is 120°
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Answer:
Given : a quadrilateral PQRS where PQ = 5.4 cm, ∠P = 60°. ∠Q = 105°, ∠R = 75° and ∠S = 120°.
To find : Construct Quadrilateral
Solution:
∠P + ∠S = 180° ∠Q + ∠R = 180°
=> PQ ║ RS
PQ = 5.4 cm
we need one more information length of Either QR , RS or PS
Step 1 : Draw a line segment PQ = 5.4 cm
Step 2 : Draw an angle of 60° at P Using protractor
Step 3 : Draw an angle of 105° at Q using protractor
Step 4 : Draw a line parallel to PQ intersecting angles drawn at R ( 105° & S (60°)
You can draw as many quadrilaterals as you want positioning RS
so we need either of length QR , RS or PS to have unique quadrilateral
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Step-by-step explanation:
steps for construction :-
1) draw line segment pq = 5.4 cm
2) draw an angle of 60 degree at point p to x and 105 degree at pont Q ti Y.
3) now from point p cuts an arc of any length at px at point S.
4) draw an angle of 120 degree at S, which meets QY at R
thus, PQRS is a required quadrilateral
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