Question

Construct a quadrilateral pqrs where PQ is equal to 5.5 CM QR 5 cm PS 4.2 CM QS 6.1 cm and Rs 7cm

Answer 1

Answer:Answer with Explanation :

PQ=4cm

QR=6cm

RS=5cm

PS=5.5cm

PR=7cm

Firstly, we will draw a rough sketch ,

PR is diagonal

Now Steps for Construction:

Step 1: Draw a line PR as diagonal (PR = 7cm)

Step 2: Draw an arc 4cm top of the PR and  P as center.

Step 3: Taking 6cm and mark arc top of the PR named Q.

Step 4: Draw an arc 5.5 cm bottom of the PR and  P as center.

Step 5: Taking 5cm and mark arc below of the PR named S.

∴ PQRS is required quadrilateral

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Answer 2

Answer:

Now Steps for Construction:

Step 1: Draw a line PR as diagonal (PR = 7cm)

Step 2: Draw an arc 4cm top of the PR and P as center.

Step 3: Taking 6cm and mark arc top of the PR named Q.

Step 4: Draw an arc 5.5 cm bottom of the PR and P as center.

Step 5: Taking 5cm and mark arc below of the PR named S.

Steps of Construction:

(i) Construct a line segment PR = 6.5 cm.

(ii) Taking P as centre and 4.5 cm radius and R as centre and 6 cm radius construct arcs which intersect each other at Q.

(iii) Now join PQ and QR.

(iv) Taking P as centre and 5 cm radius and R as centre and 5.5 cm radius, construct arcs which intersect each other at S.

(v) Join PS and SR.

Hence, PQRS is the required quadrilateral.