Question

construct a quadrilateral PQRS where PQ=PS=6cm, RS=5.4cm,/P=90°,and/120°.​

Answer 1

Answer:

Steps of Construction:

(i) Construct a line segment QR = 6 cm.

(ii) At the point Q, construct a ray QX making an angle of 90

⋅

and cut off QP = 4 cm.

(iii) At the point P, construct a ray making an angle of 60

⋅

and at R, a ray making an angle 120

⋅

which meets each other at the point S.

Therefore, PQRS is the required quadrilateral.

solution