Math, asked by yroli386, 4 months ago

Construct a quadrilateral PQRS where PQ= QR=6cm,Angle Q =135° angle R =60°and angleS=55°​

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Answered by XxBadCaptainxX
21

Answer in attachment.

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Answered by ʙʀᴀɪɴʟʏʜᴀɴᴅꜱᴏᴍᴇ
195

Your answer...

Steps of Construction:

Steps of Construction:(i) Construct a line segment QR = 6 cm.

Steps of Construction:(i) Construct a line segment QR = 6 cm.(ii) At the point Q, construct a ray QX making an angle of 90⋅ and cut off QP = 4 cm.

Steps of Construction:(i) Construct a line segment QR = 6 cm.(ii) At the point Q, construct a ray QX making an angle of 90⋅ and cut off QP = 4 cm.(iii) At the point P, construct a ray making an angle of 60⋅ and at R, a ray making an angle 120⋅ which meets each other at the point S.

Steps of Construction:(i) Construct a line segment QR = 6 cm.(ii) At the point Q, construct a ray QX making an angle of 90⋅ and cut off QP = 4 cm.(iii) At the point P, construct a ray making an angle of 60⋅ and at R, a ray making an angle 120⋅ which meets each other at the point S.Therefore, PQRS is the required quadrilateral.

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