Construct a quadrilateral PQRS where PQ= QR=6cm,Angle Q =135° angle R =60°and angleS=55°
Answers
Answer in attachment.
Mark me as brainliest
![](https://hi-static.z-dn.net/files/dce/4f3cb358d620ae664630e38de5b9705c.jpg)
Your answer...
Steps of Construction:
Steps of Construction:(i) Construct a line segment QR = 6 cm.
Steps of Construction:(i) Construct a line segment QR = 6 cm.(ii) At the point Q, construct a ray QX making an angle of 90⋅ and cut off QP = 4 cm.
Steps of Construction:(i) Construct a line segment QR = 6 cm.(ii) At the point Q, construct a ray QX making an angle of 90⋅ and cut off QP = 4 cm.(iii) At the point P, construct a ray making an angle of 60⋅ and at R, a ray making an angle 120⋅ which meets each other at the point S.
Steps of Construction:(i) Construct a line segment QR = 6 cm.(ii) At the point Q, construct a ray QX making an angle of 90⋅ and cut off QP = 4 cm.(iii) At the point P, construct a ray making an angle of 60⋅ and at R, a ray making an angle 120⋅ which meets each other at the point S.Therefore, PQRS is the required quadrilateral.
Hope it helps uh !!!
Aap bar bar unfollow kkrh ???
![](https://hi-static.z-dn.net/files/d98/49b9276b1d76a8b4c6055454b91452c4.jpg)