Math, asked by parzival7121, 1 month ago

Construct a quadrilateral PQRS with PQ = 5.7 cm, QR = 6.5 cm, RS = 4.5 cm, PR = 5.5 cm and QS = 7 cm.​

Answers

Answered by Aleezaplassery
1

Answer:

Steps of Construction:

(i) Construct a line segment PR = 6.5 cm.

(ii) Taking P as centre and 4.5 cm radius and R as centre and 6 cm radius construct arcs which intersect each other at Q.

(iii) Now join PQ and QR.

(iv) Taking P as centre and 5 cm radius and R as centre and 5.5 cm radius, construct arcs which intersect each other at S.

(v) Join PS and SR.

Hence, PQRS is the required quadrilateral.

Attachments:
Answered by kartik597652
1

Answer:

Step-by-step explanation:

Steps of Construction:

(i) Construct a line segment PR = 5.7 cm.

(ii) Taking P as centre and 4.5 cm radius and R as centre and 6 cm radius construct arcs which intersect each other at Q.

(iii) Now join PQ and QR.

(iv) Taking P as centre and 5 cm radius and R as centre and 5.5 cm radius, construct arcs which intersect each other at S.

(v) Join PS and SR.

Hence, PQRS is the required quadrilateral.

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