construct a quadrilatral ABCD in which /_B = 70°, /_ A = 54° /_D = 105° , AB 6.2 cm and AD = 5.7 cm.
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⇒ Draw a line segment AB=6cm.
⇒ With B as a center and radius BC=4cm, draw an arc.
⇒ With A as a center and radius AC=8cm, draw an arc intersecting the previous arc at point C.
⇒ Again take B as a center and radius BD=7cm, draw an arc.
⇒ With C as a center and radius CD=7cm, draw an arc intersecting the previous arc at point $$D$4.
⇒ Join AC,BC,BD,CDandAD.
Thus, ABCD is a required quadrilateral.
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