Math, asked by Ranjanapatware, 23 hours ago

Construct a quatldrilateral pqrs in which pq =6cm ,RS=2.7 cm ,QR=5.6 cm and angle q=45 angle r=90.

please solve these question​

Answers

Answered by chaudharysatyaprakas
1

Answer:

Given : PQ = 6 cm , QR = 5.6 cm , RS = 2.7 cm , ∠ Q = 45 ∘ , ∠ R = 90 ∘ ∠Q=45∘,∠R=90∘ Construction : Step 1 : Draw segment PQ of length 6 cm. Step 2 : Draw angle Q of 45 degrees. Step 3 : Taking Q as centre draw arc of radius 5.6 cm which cuts the segment BX. Point of intersection is R. Step 4 : Draw angle R of 90 degrees. Step 5 : Taking R as centre draw arc of radius 2.7 cm which cuts the segment RY. Point of intersection is S. Step 6 : Join PS. PQRS is the required quadrilateral.Read more on Sarthaks.com - https://www.sarthaks.com/1140311/construct-a-quadrilateral-pqrs-in-which-pq-6cm-qr-5-6cm-rs-2-7cm-q-45-and-r-90

Answered by SameksaAzhagiri
1

Write construction on your own so that you will understand the basic.

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