Question

construct a rectangle whose length is twice its breadth and perimeter=the perimeter of a rhombus of side 6cm

Answer 1

side of the Rhombus is 6 cm and its perimeter is 24 cm.

considering the breadth of the rectangle as x, length will be 2x

hence, 2(x+2x)=24

so,6x=24

therefore, x=24/6=4

this indicates that the breadth of the rectangle is 4 cm and the length is 8 cm

Answer 2

Let the length be 2xcm

Breadth=xcm

Given,one side of the rhombus =6 cm

Therefore, perimeter of the rhombus

=(6×4)cm

=24cm

Therefore, Perimeter of the rectangle

OR, 2 (2x+x)=24

6x=24

x=24/6

×=4

Therfore length =8m

Width=4 cm

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Step-by-step explanation: