Question

Construct a rectangle whose lingth is twice its width and perimeter is equal to the perimeter of a rhombus of side 6 cm

Answer 1

Answer:

b=4cm, l=8cm

Step-by-step explanation:

let b=x

l=2x

perimeter of rhombus=4*6=24sq.cm

perimeter of Rectangle=24

=>2(l+b)=24

=>2x+x=24/2

=>3x=12

=>x=12/3

=>x=4cm

b=4cm, l=8cm