Question

Construct a rectangle whose perimeter is 24 cm and one of its sides is 5 cm.​

Answer 1

Answer:

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Answer 2

$Let \: l \:and \: b \: are \: length \: and \\ breadth\: of \: a \: rectangle$

$Let \: b = 5 \:cm (given)$

$Perimeter \: of \:the \: rectangle = 24 \:cm$

$\implies 2( l + b ) = 24$

$\implies l + 5 = \frac{24}{2}$

$\implies l = 12 - 5$

$\implies l = 7 \:cm$

Construction steps:

1. Draw a line segment (length) AB = 7 cm .
2. Draw <BAX = 90° .
3. Centre A with radius 5 cm draw an arc which intersects AX at D .
4. Take B and D as centres and 5 cm and 7cm radii draw two arcs which intersects at C .
5. Join B and D to C .
6. Required Rectangle ABCD forward.

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