Math, asked by shubhamsinghra65, 4 months ago

Construct a regular quadrilateral inscribed in a circle of a radius of 2 cm.​

Answers

Answered by khushigavel74
1

Answer:

radius of 2cm then Inscribed a circle

Answered by lodhiyal16
0

Answer:

Step-by-step explanation:

Regular quadrilateral is inscribed in a circle therefore Diagonal of quadrilateral is the diameter of a circle.

Regular quadrilateral have equal length of sides,  

So, AB=BC=CD=DA.

Also, ∠ADC=90 °

 

By Pythagoras theorem;

AC ²  =AD ² +CD²

 

AD=CD.

Thus, AC²  =AD ²  +AD  ²

 Hence, AC= √ 2  AD    

AD=  1/√2   AC

AD= 1/√2 ×4

AD = 2√2 cm

The side of the quadrilateral is 2√2 cm.

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