Math, asked by Kathnews, 10 hours ago

Construct a rhombus ABCD in which AB=5cm and BD=7cm

Answers

Answered by Anonymous
7

Answer:

Steps of construction:

Draw one of the diagonal AC = 7 cm as base.

Draw perpendicular bisector of AC which intersects at O.

Take O as centre and cut an arc of OD = 2.5 cm above and OB = 2.5 cm below the bisector line.

Join AD, DC, AB and BC.

Hence, ABCD is the required rhombus

Step-by-step explanation:

Answered by hunnysingh0113
10

Answer:

Steps To Construct

1. Draw one of the diagonal AC = 7 cm as base. 2. Draw perpendicular bisector of AC which intersects at O. 3. Take O as centre and cut an arc of OD = 2.5 cm above and OB = 2.5 cm below the bisector line. 4. Join AD, DC, AB and BC. Hence, ABCD is the required rhombus.

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