Construct a rhombus ABCD such that where AB=7cm and angle A =60° with steps of constructions pls give a related and complete answer
Answers
Step-by-step explanation:
Given: AB=7 cm and ∠A=60
∘
.
Steps for construction
Step 1 : Draw a rough diagram and mark the given measurements.
Step 2 : Draw a line segment AB=7 cm.
Step 3 : At A on
AB
make ∠BAX whose measure is 60
∘
.
Step 4 : With A as centre draw an arc of radius 7 cm. This cuts \vec {AX} at D.
Step 5 : With B and D as centres draw arcs of radius 7 cm and let them cut each other at C.
Step 6 : Join
BC
and
DC
.
ABCD is the required rhombus.
Step 7 : Measure the lengths AC and BD.
AC=d
1
=12.2 cm and BD=d
2
=7 cm.
Answer:
Given: AB=7 cm and ∠A=60
∘
.
Steps for construction
Step 1 : Draw a rough diagram and mark the given measurements.
Step 2 : Draw a line segment AB=7 cm.
Step 3 : At A on
AB
make ∠BAX whose measure is 60
∘
.
Step 4 : With A as centre draw an arc of radius 7 cm. This cuts \vec {AX} at D.
Step 5 : With B and D as centres draw arcs of radius 7 cm and let them cut each other at C.
Step 6 : Join
BC
and
DC
.
ABCD is the required rhombus.
Step 7 : Measure the lengths AC and BD.
AC=d
1
=12.2 cm and BD=d
2
=7 cm.