Question

Construct a rhombus ABCD where AC = 7 cm and BD = 4 cm.
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Answer 1

Answer:

Steps of construction:

Steps of construction:Steps of construction:

Steps of construction:Steps of construction:Draw one of the diagonal AC = 7 cm as base.

Steps of construction:Steps of construction:Draw one of the diagonal AC = 7 cm as base.Draw perpendicular bisector of AC which intersects at O.

Steps of construction:Steps of construction:Draw one of the diagonal AC = 7 cm as base.Draw perpendicular bisector of AC which intersects at O.Take O as centre and cut an arc of OD = 2.5 cm above and OB = 2.5 cm below the bisector line.

Steps of construction:Steps of construction:Draw one of the diagonal AC = 7 cm as base.Draw perpendicular bisector of AC which intersects at O.Take O as centre and cut an arc of OD = 2.5 cm above and OB = 2.5 cm below the bisector line.Join AD, DC, AB and BC.

Steps of construction:Steps of construction:Draw one of the diagonal AC = 7 cm as base.Draw perpendicular bisector of AC which intersects at O.Take O as centre and cut an arc of OD = 2.5 cm above and OB = 2.5 cm below the bisector line.Join AD, DC, AB and BC.Hence, ABCD is the required rhombus.

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Answer 2

Answer:

$\huge \fbox \red{❥ Answer}$

Step-by-step explanation:

Draw a diagonal AC=7 cm.

2. Draw a perpendicular bisector of AC, let the perpendicular bisector and AC intersects at O (∵ Diagonals of rhombus intersects at right angle)

3. Taking O as centre and half of the length of another diagonal (i.e 3.5 cm) as radius, mark arc on the perpendicular bisector at both sides of AC. Name these intersection points as B and D

4. Join AB,AD,BC,CD.

5. ABCD is the required rhombus.

6. Measure the ∠ABD which come out to be 40.7˚