Question

Construct a rhombus ABCD where diagonals AC = 5 cm and BD = 6.8 cm.

Answer 1

Answer:

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Explanation:

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Answer 2

Construction of a rhombus

Explanation:

Construct a rhombus ABCD where diagonals AC = 5 cm and BD = 6.8 cm.

We know that diagonals of a rhombus are perpendicular bisectors of each other

Construction:

1. Draw a line segment AC  = 5 cm using a ruler.
2. With A as center and radius as a litter less than AC draw two arcs on top and bottom of the line AC. Now repeat this with C as center and the same radius so the previous two arcs are intersected at P and R.
3. Join PR. PR will be the perpendicular bisector of AC at O.
4. With O as center and 1/2 BD as radius (3.4 cm) draw two arcs to cut PR on either side of AC. Mark the points as B and D.
5. Join AB, BC, CD & DA.
6. ABCD is the required rhombus.