construct a rhombus abcd with ab=5cm,angle b=45degree
Answers
Answer:
Suppose you can get a horizontal segment with AB=5 cm.
Then, do this:
Draw a circle around A so that B is on it.
Draw a circle around B so that A is on it.
Mark the two points in which these two circles intersect as C (“above” the line) and D (“below” the line).
The polygon ACBD will be the required rhombus.
It is pretty easy to see that both triangles ABC and ABD are equilateral (since they are all formed by radii of equal lengths.
The only catch is, as Gregory Allen mentions, is that under classical compass-straightedge rules, we cannot measure distances. But if you consider “5 cm” as some sort
Step-by-step explanation:
If by “construct” you mean a classical Euclidean construction using just a compass and straight-edge then you can’t. First, a straight edge isn’t a ruler, i.e. it doesn’t have any distance markings, so there’s no way to measure out a specific distance like 5 cm.
Second, (and I could be wrong about this one) there are very few angles that can be explicitly constructed, i.e. you can’t pick an arbitrary angle size and construct an angle of that measure. I don’t believe a 60 degree angle is one of those special angles.