Construct a rhombus ABCD with diagonals AC=6 cm and BD=8 cm.
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Step-by-step explanation:
Draw AC = 8 cm.
Draw perpendicular bisector of AC = cut it at I.
Cut IB = 6/2 = 3 cm and ID = 3 cm and join ABCD. Then ABCD is the required rhombus.
Now from I draw a perpendicular to BC to meet it at L.
With I as centre and IL as radius, draw a circle which is the required circle. Its radius = IL 2.4
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