Math, asked by acricketits001, 3 months ago

Construct a rhombus ABCD with diagonals AC-6 cm and BD=8 cm​

Answers

Answered by divyanisinhabgp1
3

Step-by-step explanation:

Steps of construction :

1. Draw AC = 8 cm.

2. Draw perpendicular bisector of AC = cut it at I.

3. Cut IB = 6/2 = 3 cm and ID = 3 cm and join ABCD. Then ABCD is the required rhombus.

4. Now from I draw a perpendicular to BC to meet it at L.

5. With I as centre and IL as radius, draw a circle which is the required circle. Its radius = IL = 2.4 cm.

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