construct a rhombus abcd with sides 4.9 cm and diagonal6.9cm
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Answer: Construct a rhombus ABCD, if ; diagonal AC = 4.9 cm and diagonal BD = 6 cm.
Explanation : Steps : 1. Draw AC = 4.9 cm. 2. Draw perpendicular bisector XY of AC. 3. Cut OB = OD = 3 cm (half the diagonal 6 cm) 4. Join AB, BC, AD and CD. Thus ABCD is the required rhombus
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Step-by-step explanation:
this rhombus looks like square because of diagnol (this is hypotenus )
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