Question

construct a rhombus BEND when BN is equal to 5.6 cm and DE is equal to 6.5 CM. ​

Answer 1

Answer:

Rhombus BEND is constructed

Step-by-step explanation:

construct a rhombus BEND when BN is equal to 5.6 cm and DE is equal to 6.5 CM. ​

Rhombus diagonald perpendiculalrly bisect each other

BN  & DE are Diagonal

Let say diagonal Bisect at P

Let draw first

BN  =  5.6 cm

Then find O such that BO = ON = 5.6/2 = 2.8 cm

Now Draw Perpendicular on BO both sides

Draw OD  & OE  = 6/5/2 = 3.25 cm

Now join

D with B & N

& E With B & N

Hence Rhombus BEND is constructed

Answer 2

Step-by-step explanation:

Constuction:-

(1) Draw a line segment BN of 5.6 cm and also draw its perpendicular bisector. Let it intersect the line segment BN at point O.

(2) Taking O as centre, draw arcs of 3.25 cm radius to intersect the perpendicular bisector at point D and E.

(3) Join points D and E to points B and N.

BEND is the required quadrilateral.