Question

Construct a Rhombus MATH where MT = 5.2cm and AH = 6.4cm

Answer 1

Answer:

Given: Diagonals of a rhombus AC = 5.2 cm and BD = 6.4 cm.

To construct: A rhombus ABCD.

Steps of construction:

(a) Draw AC = 5.2 cm and draw perpendicular bisectors on AC.

(b) Since, diagonals bisect at mid-point O, therefore get half of 6.4 cm, i.e., 3.2 cm.

(c) Draw two arcs on both sides of AC of radius 3.2 cm from intersection point O, which  intersects at B and D.

(d)Join AB, BC, CD and DA.

It is required rhombus ABCD.