Question

Construct a rhombus PQRS given PR = 8.4 cm and QS = 5.6 cm.

Answer 1

Answer:

hlo Brainly user ❤️

Step-by-step explanation:

Given: PR=8 cm and QS=6 cm.

Steps for construction

Step 1 : Draw a rough diagram and mark the given measurements.

Step 2 : Draw a line segment PR=8 cm

Step 3 : Draw the perpendicular bisector

XY

to

PR

. Let it cut

PR

at "O".

Step 4 : With O as centre and 3 cm (half of QS) as radius draw arcs on either side of

′

O

′

which cuts

XY

at Q and S as shown in fig.

Step 5 : Join

PQ

,

QR

,

RS

and

SP

.

PQRS is the required rhombus.

Step 6 : We know, PR=d

1

=8 cm and QS=d

2

=6 cm.

Calculation of area:

In the Rhombus PQRS,

d

1

=8 cm and d

2

=6 cm.

Area of the rhombus PQRS

=

2

1

×d

1

×d

2

=

2

1

×8×6

=24 cm

2

.