Construct a rhombus PQRS given PR = 8.4 cm and QS = 5.6 cm.
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Answer:
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Step-by-step explanation:
Given: PR=8 cm and QS=6 cm.
Steps for construction
Step 1 : Draw a rough diagram and mark the given measurements.
Step 2 : Draw a line segment PR=8 cm
Step 3 : Draw the perpendicular bisector
XY
to
PR
. Let it cut
PR
at "O".
Step 4 : With O as centre and 3 cm (half of QS) as radius draw arcs on either side of
′
O
′
which cuts
XY
at Q and S as shown in fig.
Step 5 : Join
PQ
,
QR
,
RS
and
SP
.
PQRS is the required rhombus.
Step 6 : We know, PR=d
1
=8 cm and QS=d
2
=6 cm.
Calculation of area:
In the Rhombus PQRS,
d
1
=8 cm and d
2
=6 cm.
Area of the rhombus PQRS
=
2
1
×d
1
×d
2
=
2
1
×8×6
=24 cm
2
.
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