Math, asked by sm140098, 1 month ago

Construct a rhombus PQRS in which diagonals PR = 6.8 cm and QS = 5.5 cm. ​

Answers

Answered by rumad0019
1

Steps-

a rhombus whose diagonal are of length 6.8cm and 8.4cm

As we know that diagonals of a rhombus perpendicualrly bisect Each other

Step 1  : Draw a line segment PR  = 6.8 cm using ruler

Step 2 : Draw a Perpendicular bisector of PR Using Compass

(Using Compass & opening it little bit less than PR and draw arcs on both sides of PR using P as Center then intersecting these two arcs taking R as Center)

Step 3 : Draw a Line joining intersection point of arcs

Step 4 : From the point where it intersect PR using compass cut this line = (8.4/2 = 4.2 cm both sides) and get point Q & S

Step 5 : Join PQ , QR , RS & PS

a rhombus whose diagonal are of length 6.8cm and 8.4cm is constructed

FOR THE DRAWING MARK ME AS BRAINLIEST...

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