Math, asked by arqish123, 11 months ago

Construct a rhombus PQRS, such that PQ= 60mm and the diagonal PR= 9mm. Measure and write the size of angle QPS.

Answers

Answered by amitnrw
17

Answer:

rhombus PQRS is constructed

Step-by-step explanation:

Construct a rhombus PQRS, such that PQ= 60mm and the diagonal PR = 9mm

Draw a line segment PR = 9 mm

Draw a perpendicular bisector of PR

(Taking a Length More than Half of PR , Draw arcs on both sides of PR  taking P as Center , Then Keppping same length & taking center as R , draw two arcs intersecting the arcs.  Draw a line passing through intersection points

Draw an arc with length = 60 mm from P  , intersecting at perpendicular bisector drawn and label then Q & S

Join PQ , PS  &

Join RQ & RS

rhombus PQRS is constructed

Answered by eshaal9425
1

Answer:

]rhombus PQRS is constructed

Step-by-step explanation:

Construct a rhombus PQRS, such that PQ= 60mm and the diagonal PR = 9mm

Draw a line segment PR = 9 mm

Draw a perpendicular bisector of PR

(Taking a Length More than Half of PR , Draw arcs on both sides of PR  taking P as Center , Then Keppping same length & taking center as R , draw two arcs intersecting the arcs.  Draw a line passing through intersection points

Draw an arc with length = 60 mm from P  , intersecting at perpendicular bisector drawn and label then Q & S

Join PQ , PS  &

Join RQ & RS

rhombus PQRS is constructed

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