Construct a Rhombus PQRS where PR = 9 cm and QS = 6 cm.Measurement of angle ROS is _____. Please answer fast
Answers
Given: PQ=6 cm and PR=9 cm.
To construct a rhombus
Steps for construction
Step 1 : Draw a rough diagram and mark the given measurements.
Step 2 : Draw a line segment PQ=6 cm.
Step 3 : With P and Q as centres, draw arcs of radii 9 cm and 6 cm respectively and let them cut each other at R.
Step 4 : Join PR and QR.
Step 5 : With P and R as centres draw arcs of radius 6 cm and let them cut each other at S.
Step 6 : Join PS and RS.
PQRS is constructed as required.
Step 7 : Measure the length of QS.QS=d2=8 cm.PR=d1=9 cm.
Answer:
Given: PR=8 cm and QS=6 cm.
Steps for construction
Step 1: Draw a rough diagram and mark the given measurements.
Step 2 : Draw a line segment PR=8 cm.
Step 3 : Draw the perpendicular bisector
XY
to
PR
. Let it cut
PR
at "O".
Step 4 : With O as centre and 3 cm (half of QS) as radius draw arcs on either side of
′
O
′
which cuts
XY
at Q and S as shown in fig.
Step 5 : Join
PQ
,
QR
,
RS
and
SP
.
PQRS is the required rhombus.
Step 6 : We know, PR=d
1
=8 cm and QS=d
2
=6 cm.
Calculation of area:
In the Rhombus PQRS,
d
1
=8 cm and d
2
=6 cm.
Area of the rhombus PQRS
=
2
1
×d
1
×d
2
=
2
1
×8×6
=24 cm
2
.