Math, asked by bhati245, 1 year ago

construct a rhombus whose diagonals are 4.5 cm and 6.2 cm​

Answers

Answered by mail2sankar117
1

Step-by-step explanation:

1. Draw a line segment AC=4.5cm.

2. Draw XY, the perpendicular bisector of AC.

3. From XY, cut-off OD=

2

1

(6.4)=3.2 cm.

4. Similarly, cut-off OB=

2

1

(6.4)=3.2 cm.

5. Join AD,DCCB and BA.

Thus, ABCD is the required rhombus.

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