construct a rhombus whose diagonals are given with diagram
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Step-by-step explanation:
⇒ Draw a line segment AC=16cm
⇒ Draw a perpendicular bisector of AC, which intersect AC at point O.
⇒ Take O as center with radius 6cm and draw an arc above and below on perpendicular, We get point B and D
⇒ Join AB,BC,CD and AD
∴ ABCD is required rhombus.
The properties which we have used are :
⇒ The intersection of the diagonals of a rhombus form 90 degree angles. This means that they are perpendicular.
⇒ The diagonals of a rhombus bisect each other. This means that they cut each other in half.
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