Math, asked by moolchand3077, 7 months ago

Construct a rhombus whose diagonals measure 8.4 cm and 4.8 cm respectively.​

Answers

Answered by chavansonu885
4

Answer:

Steps of construction:

a) Draw AC = 8cm.

b) Draw perpendicular bisector XY of

AC meeting AC at 0.

1

c) From O cut off OD = 2 x6 cm = 3

1

cm along OX and OB = 2 x6 cm =3

cm along Oy.

d) Join AB, BC, CD, and DA.

ABCD is the required rhombus

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