Construct a rhombus with side 4.2 and one of its angles 65°
Answers
Answered by
1
Let the be ABCD
AB = BC = CD = CA = 4.2
Angle ABC= 65°
opposite angle are equal
So angle ABC = angle CDA = 65°
angle DAB = angle BCD
= {360°- (65° + 65°)}/2
= (360° - 130°)/2
= 230°/2
= 115°
AB = BC = CD = CA = 4.2
Angle ABC= 65°
opposite angle are equal
So angle ABC = angle CDA = 65°
angle DAB = angle BCD
= {360°- (65° + 65°)}/2
= (360° - 130°)/2
= 230°/2
= 115°
Similar questions
Accountancy,
7 months ago
Hindi,
1 year ago