Construct a rhombus with side 4.2 and one of its angles 65°
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Let the be ABCD
AB = BC = CD = CA = 4.2
Angle ABC= 65°
opposite angle are equal
So angle ABC = angle CDA = 65°
angle DAB = angle BCD
= {360°- (65° + 65°)}/2
= (360° - 130°)/2
= 230°/2
= 115°
AB = BC = CD = CA = 4.2
Angle ABC= 65°
opposite angle are equal
So angle ABC = angle CDA = 65°
angle DAB = angle BCD
= {360°- (65° + 65°)}/2
= (360° - 130°)/2
= 230°/2
= 115°
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