construct a rhombus with side lenght 3.5cm and one of its diagonal as 4.6cm .
Answers
Answer:
StepSteps:
Draw AB=4.5cm
A as centre,draw an arc with radius 6cm.
With B as centre draw an arc, cutting previous arc.
Mark the intersecting point as C
With C as centre draw an arc with radius 4.5cm
With A as centre draw an arc with same radius.
Mark the intersecting point as D
Join D to C , A-C, B to C and A to C.
Thus ABCD is the required rhombus.
Other diagonal BD is 7cm.
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-by-step explanation:
Answer:
We know that in rhombus all sides are equal. To construct a rhombus whose side is of length 3.4 cm and one of its angle is 45°, use the following steps
1. Draw a line segment AS of length 3.4 cm.
2. Now, generate an angle 45° at both ends A and B of line segment AB and plot the parallel lines AX and BY.
3. Cut AD and SC of length 3.4 cm from AX and BY, respectively.
4. Draw an angle of 45° at one of the point D or C and join both points by a line segment DC of length 3.4 cm and parallel to AB.
Thus, ABCD is the required rhombus whose side is of length 3.4 cm and one of its angles is 45°.
Alternate Method
To construct a rhombus whose side is of length 3.4 cm and one of its angle is 45°, use the following steps.
1. Draw a line segment AB of length 3.4 cm.
2. Now, draw an angle XAB = 45° at point A of line segment AB.
3. Cut a line segment AD = 3.4 cm from the ray AX and join BD.
4. Now, D point C is at a distance of 3.4 cm. So, having D as the center draw an arc of radius 3.4 cm.
5. From B, point C is a distance of 3.4 cm. So, having B as the center draw an arc of radius 3.4 cm which intersects the previous arc (obtained in step iv) at C.
6. Join CD and BC.
Thus, ABCD is required rhombus whose side is of length 3.4 cm and one of its angle is 45°.
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