Math, asked by 5563stkabirdio, 3 days ago

Construct a Rhombus WXYZ such that WX = 6 cm and Angle X = 105°
(Use compass to make 105°)

Answers

Answered by meghamegha434
0

. A rhombus whose diagonals are 5.2 cm and 6.4 cm long.

Sol. Let diagonal AC = 5.2 cm and diagonal BD = 6.4 cm

Draw AC = 5.2 cm. Draw XY, the perpendicular bisector of AC which cuts AC at O.

With O a centre, draw arcs of radii

which cut OX at D and OY at B.

Join AB, BC, CD and DA.

Then, ABCD is the required rhombus.

3. A rectangle with adjacent sides of lengths 5 cm and 4 cm.

Sol. In a rectangle, opposite sides are equal and each of 4 angles is equal to 90°.

Let AB = DC = 5 and BC = 4 cm

∴AB = DC = 5 cm and BC = AD = 4 cm.

Also, ∠A = ∠B = ∠C = ∠D = 90°.

Steps of construction

1. Draw AB = 5 cm.

2. Draw ∠ABX = 90°.

3. Cut off BC = 4 cm on BX.

4. With A as centre and radius equal to 4 cm, cut off an arc.

5. With C as centre and radius equal to 5 cm cut off another arc on the arc drawn in step-4 at point D.

6. Join AD and CD.

Hence, ABCD is the required

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