Construct a right angeled triange PQR,in PQ=5cm, hypotenuse,QR=9CM
Please send with the nessesary calculations
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Step-by-step explanation:
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Answer:
Step-by-step explanation:
Find PR:
by pythogoras theorum, hypotenuse∧2 = adjacent∧2+ opposite∧2
So,for ΔPQR, QR∧2 = PQ∧2+PR∧2
PR∧2 = QR∧2-PQ∧2
PR=√QR∧2-PQ∧2
PR = √9∧2-5∧2
=√81-25
=√56
PR = 7.483 cm
I can only give the length of PR. Please give angle measurements of either one for a more accurate answer for drawing purposes.
Otherwise it has to be done with Trial & Error.
I hope this has been helpful to you.
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