Question

Construct a right angle triangle def such de =ef and df = 10 cm

Answer 1

$\triangle efd$ is the required triangle where $de =ef$ and $df = 10\ cm$.

Step-by-step explanation:

Given,

Construct a right angle $\triangle efd$ such $de =ef$ and $df = 10\ cm$

Following steps:

• Draw a line segments $df = 10\ cm$ using scale.
• Draw a perpendicular line $dm$ through $d$ such that $dm\perp df$
• Bisect the $\angle fdm$ with line $dp$
• Similarly draw an $\angle dfa$ at $f$ such that $\angle fdp=\angle dfa$
• Line $dp$ and $fa$ intersect at point $e$

Hence, $\triangle efd$ is the required triangle where $de =ef$ and $df = 10\ cm$.