construct a right angle triangle pqr in which hypotenuse PR equal to 8 cm and PQ equal to 6
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Answered by
7
Answer:
һєʟʟʟo mѧţє һєяє ıs uя ѧňsɰєя ❤
Step-by-step explanation:
of Construction: i)
Draw a line segment QR = 4.5 cm
2)At Q, draw a ray QX making an angle of 90
°
With centre R and radius 8 cm, draw an arc which intersects QX at P. iv)
Join RP. ΔPQR is the required triangle.
v) Draw the bisector of ∠PQR which meets PR in T. vi) From T, draw perpendicular PL and PM respectively on PQ and QR. Proof: In ΔLTQ and ΔMTQ ∠TLQ = ∠TMQ (Each = 90°) ∠LQT = ∠TQM (QT is angle bisector) QT = QT (Common) ∴ By Angle – Angle – side criterion of congruence, ∴ΔLTQ ≅ ΔMTQ (AAS postulate) !!
ı һopє ıţs һєʟp u ✌
Answered by
11
- First, draw a line segment PQ of 6 cm.
- Next, take a protractor and keep it's mid-point on the point Q and draw a ray measuring 90°.
- Then, take a compass and measure it as 8 cm and keep it's tip on the point P and draw an arc on the ray drawn.
- Now, join the point where the ray and the arc meets. Name it as point R.
- Finally, the triangle is constructed.
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☯ Ruler :- The ruler is used to draw the lines of accurate measurements and the drawn lines should be correct and straight always.
☯ Protractor :- The protractor is used to draw the rays of accurate measurements of degrees. It's also used to measure the angles given.
☯ Compass :- The compass is used to draw the arcs on the ray by taking the measurements from ruler.
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