Question

construct a right angle triangle pqr such that angle Q equal to 90° PQ is equal to 8 cm and PR is equals to 10 cm​

Answer 1

Answer:

1. Draw PQ = 10cm

2.Taking Q as centre , draw a semi circle of any radius usnig a compass

3. Without changing the radius cut an arc from M and then from N.

4. From both the arcs cut an arc.

5. Draw a line from Q passing through the arc .

and mark it as QX

6.From P taking a radius of 10cm cut an arc on QX.

7. Join PR.

8.Therefore, PQR is the required triangle.