Construct a right angle triangle whose base is 12 cm and sum of its hypotenuse and other side is 18 cm
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1 .draw a base BC =12cm
2 .now let's draw a with B=90°
3 .let the ray be BX
4 .open the compass to the length AB+AC=18cm
5 .from point B as center cut an arc on ray BX
6 .let the arc intersect BX at D
7 .join CD
8 .then draw a perpendicular bisector intersects BD
9 .join AC
10 .therefore, ABC is the required triangle
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