Question

Construct a right angle whose base is 8 cm and sum of its hypotenuse and the other side is 14 cm.

Answer 1

a^2+b^2=c^2
b+c=14
64+b^2=(14-b)^2
64+b^2=196+b^2-28b
28b=132
b=4.714
c=9.286

Answer 2

1. Draw a line segment AB=8
2. Construct 90° at A
3. Extend it to AX
4. Take A as a centre and draw an arc of 14cm.
5. Mark the point of intersection of the arc and AX as D.
6. Join D to B with dots or a dotted line
7. Draw a perpendicular bisector of the BD
8. The point where the perpendicular bisector meets AX is C
9. Join C to A
10. You will get the required right angled triangle