construct a right angled-isosceles triangle with hypotenuse 8cm
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here we can take AC as hypotenuse an AB and BC as it's other sides
AC^2=BC^2+AB^2
8^2=BC^2+BC^2
64=2BC^2
32=BC^2
BC=√32
hence 64=(√32)^2+(√32)^2
so ABC is a right angeled isosceles triangel
AC^2=BC^2+AB^2
8^2=BC^2+BC^2
64=2BC^2
32=BC^2
BC=√32
hence 64=(√32)^2+(√32)^2
so ABC is a right angeled isosceles triangel
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kjc1:
the value of BC is unroot 32
srry I had done a mistake
I will change the answer
ok
now
pls mark it as brainliest answer
this is absolutely wrong answer
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