construct a right angled triangle ABC in which AB = 8 cm , BC = 6 cm and angle B = 90 degree
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Take BD= y cm,
AB = 8 cm,
BC= 6 cm.
So, Mark, AD= 6.4 cm,
On point D with the help of compass make an angle of 90° which will pass through B.
To Draw a circle passing through points B, D, A that is Circumcircle .
You can draw by taking any two line segments BD and DA and drawing its perpendicular bisector.
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Let ABC be the right angled triangle such that ∠B = 90° , BC = 6 cm, AB = 8 cm. Let O be the centre and r be the radius of the in circle.
AB, BC and CA are tangents to the circle at P, N and M.
∴ OP = ON = OM = r (radius of the circle)
By Pythagoras theorem,
CA2 = AB2 + BC2
⇒ CA2 = 82 + 62
⇒ CA2 = 100
⇒ CA = 10 cm
Area of ∆ABC = Area ∆OAB + Area ∆OBC + Area ∆OCA......(rest is in pic)
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