construct a right - angled triangle ABC such that AB = 8 cm and hypotenuse AC 10 cm.
Answers
Answered by
1
Answer:
Each part: 2 Marks
(a) Draw a line segment
¯¯¯¯¯¯¯¯
B
C
=
8
c
m
Draw
∠
C
B
D
=
90
∘
at B using compass.
With C as centre and radius equal to 10 cm, draw an arc to cut the ray
¯¯¯¯¯¯¯¯¯
B
D
at A and join
¯¯¯¯¯¯¯¯
A
C
.
ABC is the required triangle.
(b) Steps of Construction:
(i) Draw BC = 5 cm.
(ii) Construct
∠
BCX = 90
∘
.
(iii) With B as centre and radius 7 cm, cut BA at 7 cm.
(iv) Join AB.
Thus, ABC is required triangle.
Answered by
2
Answer:
Let AB=BC=a
Since ABC is a right angled triangle ,
∴
a
2
+a
2
=8.0
⇒
2
a=8.0
⇒a=5.6 cm
1. Draw the base side BC=5.6 cm
2. At point B, draw an angle of 90
∘
3. At point C, draw an arc of AC=8.0 cm intersecting the arm of the angle 90
∘
and the arc drawn in step 2
4. Name the point of intersection, as A
5. ABC is the required triangle
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