Question

construct a right angled triangle ABC, whose hypotenuse is 10cm long and one of the leg is 8cm?​

Answer 1

${h}^{2} = {b}^{2} + {p}^{2} \\ \\ ( {10)}^{2} = {b}^{2} + ( {8)}^{2} \\ \\ 100 = {b}^{2} + 64 \\ \\ 100 - 64 = {b}^{2} \\ \\ 36 = {b}^{2} \\ \\ \sqrt{36} = b \\ \\ 6 = b$

Answer 2

$\bold{ {h}^{2} = { b}^{2} + {p}^{2} }$

$\bold{ \implies \: {10}^{2} = {b}^{2} + {8}^{2} }$

$\bold{ \implies \: {b}^{2} = {10}^{2} - {8}^{2} }$

$\bold{ \implies {b}^{2} = 100 - 64}$

$\bold{ \implies \: {b}^{2} = 36 }$

$\bold{ \implies \: {b}^{2} = {6}^{2} }$

$\bold{ \implies \: b = 6}$