Construct a right angled triangle PQR right angled at P, PQ is 4 cm and PR is 6cm
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Step-by-step explanation:
Given: PQ=10cm, PR=24cm
Let QR be x cm.
In right angled triangle QPR,
(Hypotenuse)
2
=(Base)
2
+(Perpendicular)
2
[By Pythagoras theorem]
⇒(QR)
2
=(PQ)
2
+(PR)
2
⇒x
2
=(10)
2
+(24)
2
⇒x
2
=100+576=676
⇒x=
676
=26cm
Thus, the length of QR is 26cm.
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