Construct a right angled triangle PQR with m∠Q = 90°, hypotenuse PR = 7 cm and QR = 5 cm.
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We know,
In right angle triangle ∠Q = 90°,shown in the figure attached.
For constructing Δ
1.Draw a line from point R to Q(RQ = 5 cm.) using scale.
2.Now Make ∠MQR=90° using protractor.
3.Now keep needle of the bow compass at R and extend equal to 7 cm. draw an arc N and chop it with.
4.Give point of intersection name P.
5.By joining point PR and PQ we got right angle ΔPQR.
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