Construct a right angled triangle with measure of hypotenuse and one of the sides by asking your friend.
Answers
Answered by
0
Let's my friend told that triangle is PQR and its one of side RQ= 5 cm.
Assume hypotenuse PQ = 6 cm.
We know,
In right angle triangle ∠R = 90°,shown in the figure attached.
For constructing Δ
1.Draw a line from point R to Q(RQ = 5 cm.) using scale.
2.Now Make ∠MRQ=90° using protractor.
3.Now keep needle of the bow compass at Q and extend equal to 6 cm. draw an arc N and chop it with.
4.Give point of intersection name P.
5.By joining point PR and PQ we got right angle ΔPQR.
Attachments:
Answered by
0
In ∆ ABC,
BC = 4 cm , BA = 3 cm ,
Hypotenuse ( AC ) = 5 cm
By Phythogarian theorem. :
AC² = AB² + BC²
Construction steps :
1 ) Draw BC = 4 cm line segment.
2 ) Take B and C as centers with
radii 3 cm and 5 cm respectively draw
two intersecting arc's . Intersecting
point is A .
3 ) Join A to B and C .
We get ∆ABC right angled triangle.
Right angle at B .
AC is Hypotenuse.
I hope this helps you.
: )
BC = 4 cm , BA = 3 cm ,
Hypotenuse ( AC ) = 5 cm
By Phythogarian theorem. :
AC² = AB² + BC²
Construction steps :
1 ) Draw BC = 4 cm line segment.
2 ) Take B and C as centers with
radii 3 cm and 5 cm respectively draw
two intersecting arc's . Intersecting
point is A .
3 ) Join A to B and C .
We get ∆ABC right angled triangle.
Right angle at B .
AC is Hypotenuse.
I hope this helps you.
: )
Attachments:
Similar questions