Question

Construct a right triangle ABC in which angle B = 90°, AB + AC = 10 cm, BC = 6 cm.
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Answer 1

Step-by-step explanation:

Draw the base BC = 6cm and at the point B make an angle 90°, say ∠XBC equal to the given angle. 2. Cut a line segment BD = 10 cm equal to AB + AC from the ray BX.

Answer 2

Step-by-step explanation:

Steps of construction:

1. Draw the base BC = 6cm and at the point B make an angle 90°, say ∠XBC equal to the given angle.

2. Cut a line segment BD = 10 cm equal to AB + AC from the ray BX.

3. Join DC and make an angle ∠DCY equal to ∠BDC

4. Let CY intersect BX at A. We constructed required ∆ABC.

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