Question

Construct a right triangle ABC, right angled at B where BC=6cm and AB+AC=10cm
Show the construction work also

Answer 1

Answer:

ANSWER:-

Steps of construction:  

1. Draw the base BC = 6cm and at the point B make an angle 90°, say ∠XBC equal to the given angle.  

2. Cut a line segment BD = 10 cm equal to AB + AC from the ray BX.  

3. Join DC and make an angle ∠DCY equal to ∠BDC

4. Let CY intersect BX at A. We constructed required ∆ABC.