Math, asked by deepakthakur222, 10 months ago

Construct a right triangle ABC with AB =6 cm BC =8 and angle 90 draw BD perpendicular from B to AC draaw a circle through B,CandD construct tangent from A to circle

Answers

Answered by anshika1810
4

there you go!!

i hope this helps

Attachments:

aaryann: mera koi best friend nhi h
anshika1810: toh?
aaryann: aap bnn jao
aaryann: Mai sab ko happy rkhta hu kisi ko sad nhi krta
Answered by amruth8
2

Ans. To construct: A right triangle ABC with AB = 6 cm, BC = 8 cm and B = BD is the perpendicular from B on AC and the tangents from A to this circle.

Steps of Construction:

(a) Draw a right triangle ABC with AB = 6 cm, BC = 8 cm and B = 90°.

Also, draw perpendicular BD on AC.

(b) Join AO and bisect it at M (here O is the centre of circle through B, C, D).

(c) Taking M as centre and MA as radius, draw a circle. Let it intersects the given circle at the points B and E.

(d) Join AB and AE.

Then AB and AE are the required two tangents.

Justification: Join OE.

Then, AEO is an angle in the semicircle.

AEO =

AE _|_OE

Since OE is a radius of the given circle, AE has to be a tangent to the circle. Similarly, AB is also a tangent to the circle.

Attachments:
Similar questions