Construct a right triangle, when one side is 3.8cm and the sum of the other side and hypotenuse is 6cm.
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Answer:
Step-by-step explanation:
Step 1: Draw a line segment BC of 3.8cm.
Step 2: At B draw an angle le x BC of 90o .
Step 3: with center B and radius 6cm draw an arc which intersects XB at D.
Step 4: Join DC.
Step 5: Draw the perpendicular bisector of DC which intersects DB at A
Step 6: Join AC
ABC is the required triangle
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Steps of construction:
i) Draw AB = 3.8cm
ii) Through B draw line BP so that ∠ABP = 900
iii) From BP cut BD = 6cm iv Join A and D. v Draw perpendicular bisector of AD which meets BD at point C.
iv) Thus ABC is the required triangle.
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