Construct a right triangle whose base is 12 cm and sum of its hypotenuse and other side is 18 centimetre
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Hello here,
Given : In right ∆ABC, base BC = 12cm, angle B = 90°
Required : To construct the right triangle ABC.
1. Draw the base BC= 12 cm
2. At the point B, make an angle XBC = 90°.
3. Cut a line segment BD = Ab + AC ( = 18 cm ) from ray BX.
4. join AC
5. Draw the perpendicular bisector PQ of CD to intersect BD at a point A.
6. Join AC.
THAN , ABC IS THE REQUIRED RIGHT TRIANGLE.
Hope this will helpful for you
<<<<<<<☺>>>>>>>
Given : In right ∆ABC, base BC = 12cm, angle B = 90°
Required : To construct the right triangle ABC.
1. Draw the base BC= 12 cm
2. At the point B, make an angle XBC = 90°.
3. Cut a line segment BD = Ab + AC ( = 18 cm ) from ray BX.
4. join AC
5. Draw the perpendicular bisector PQ of CD to intersect BD at a point A.
6. Join AC.
THAN , ABC IS THE REQUIRED RIGHT TRIANGLE.
Hope this will helpful for you
<<<<<<<☺>>>>>>>
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