Construct a right triangle whose base is 3.5 cm and sum of its hypotenuse and other side is 5.5 cm and give justification.
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Answer:
- Construct BC = 3.5 cm
- Construct ∠CBX = 90°
- From BX cut off line segment BD = AB + AC = 5.5 cm
- Join the points CD
- Construct the perpendicular bisector of CD which meets the line BD at point A
- Join AC.
Therefore, △ABC is the required triangle.
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Draw a line segment AB = 3.5 cm.
Draw a ray AX from A at 90°.
Draw an arc on AX with a radius of 5.5 cm.
Mark this point as C.
Join BC.
Measure ACB and draw a ray BY from B such that ∠ACB = ∠CBY and BY passes through AC.
Mark the point where ray BY meets AC as D.
ABD is the required triangle.
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